Trap The Cat - Unblocked

if (dist < HEX_SIZE * 0.9) // Click logic if (grid[y][x] === 0 && !(x === catPos.x && y === catPos.y)) grid[y][x] = 1; // Place wall catTurn();

// Place Cat catPos = x: Math.floor(COLS/2), y: Math.floor(ROWS/2) ; grid[catPos.y][catPos.x] = 2;

// Check if actually trapped if (!moved) endGame(true); return;

: Don't place blocks directly next to the cat immediately. The cat can easily sidestep tight blocks. Instead, build a wide "ring" or arc several tiles away to cut off entire sections of the board. trap the cat unblocked

Winning requires thinking several moves ahead rather than just reacting to the cat's current position.

// 3. Move Cat if (foundPath && foundPath.length > 0) // Move along path moveCat(foundPath[0]); else // No path to edge? Try to move to any available spot (Stall) // Or if fully trapped, Game Over (Win) const neighbors = getNeighbors(catPos.x, catPos.y); let moved = false; for (let n of neighbors) if (grid[n.y][n.x] === 0) moveCat(n); moved = true; break;

return px, py ;

: Use a distinct marker, like a coin, a button, or a dark-colored pawn, to represent the cat. Start it in the center hex.

function drawHex(x, y, type) const px, py = getPixelPos(x, y);

// Draw Cat if (type === 2) ctx.font = '24px Arial'; ctx.textAlign = 'center'; ctx.textBaseline = 'middle'; ctx.fillText(catEmoji, px, py); if (dist &lt; HEX_SIZE * 0

hexes. If drawing hexes is too difficult, you can use a staggered circular grid where each "dot" is connected to six neighbors.

// --- AI Logic (BFS Pathfinding) --- function getNeighbors(x, y) const neighbors = []; // Directions differ based on odd/even column const oddColDirs = [[+1, -1], [+1, 0], [0, +1], [-1, 0], [-1, -1], [0, -1]]; const evenColDirs = [[+1, 0], [+1, +1], [0, +1], [-1, +1], [-1, 0], [0, -1]];

const rect = canvas.getBoundingClientRect(); const mouseX = e.clientX - rect.left; const mouseY = e.clientY - rect.top; Winning requires thinking several moves ahead rather than