@dataclass class Building: name: str size: Tuple[int, int] # width, height in tiles category: str # residential, production, infrastructure required_roads: int # sides requiring road access coverage_radius: int = 0 # for markets/churches output: str = None # resource produced input: List[str] = None # resources consumed
score = calculate_layout_score(optimizer) print(f"Tax revenue: score['tax_revenue'] gold/min") print(f"Space efficiency: score['space_utilization']*100:.1f%")
: Ensure safety buildings like the Carpenter and Fire Station cover every single residence. While a house can function without them for a time, a single fire or collapse can quickly snowball into a city-wide disaster. Popular Layout Strategies Players often choose between two main philosophies: Building layout strategies | Anno 1404 Wiki | Fandom anno 1404 stadt layout
Perfecting your (city layout) is the key to evolving from a small village into a sprawling metropolis filled with thousands of Noblemen. An efficient layout ensures that every house has access to necessary public buildings like marketplaces, churches, and taverns without wasting valuable island space. Core Principles of Anno 1404 City Design
For massive populations, create a repeatable "district" pattern. For example, a 40x40 module can hold approximately 102 houses plus a Chapel and Marketplace. These can be tiled across an island. @dataclass class Building: name: str size: Tuple[int, int]
In Anno 1404 , residents have specific needs (like Marketplaces and Chapels) and safety requirements (Fire Stations, Carpenters, and Surgeries). Effective layouts maximize the number of houses within these influence zones.
A well-designed Stadt layout should balance functionality, efficiency, and aesthetics. Here are some key principles to keep in mind: An efficient layout ensures that every house has
class LayoutOptimizer: def (self, width: int = 50, height: int = 50): self.grid = np.zeros((width, height), dtype=int) # 0=empty, 1=road, 2=building self.buildings = [] self.resource_zones = {}
bread_chain = optimizer.optimize_production_chain( "wheat_farm": 4, "mill": 2, "bakery": 2 )