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Answer: Total resistance ( R = 5 + 8 + 12 = 25 , \Omega ) Current ( I = V/R = 6/25 = 0.24 , \textA ) (ammeter reading) Voltage across 12 Ω = ( I \times 12 = 0.24 \times 12 = 2.88 , \textV ) (voltmeter reading)
): The work done per unit positive charge to move it from infinity to a specific point. Unit: The SI unit is Volt ( ) .
By following this comprehensive guide to Class 10 Electricity NCERT Solutions, students can develop a thorough understanding of the concepts and principles of electricity, which will help them build a strong foundation in physics and prepare them for future studies. class 10 electricity ncert solutions
Answer: Thick wire — because resistance decreases with increase in area.
The solutions demonstrate a step-by-step method: Answer: Total resistance ( R = 5 +
A closed circuit is a circuit in which the current flows continuously, whereas an open circuit is a circuit in which the current does not flow.
Q7. The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below: I (amperes) : 0.5, 1.0, 2.0, 3.0, 4.0 V (volts) : 1.6, 3.4, 6.7, 10.2, 13.2 Plot V–I graph and calculate resistance. Slope ( \Delta V / \Delta I ) ≈ 3.3 Ω. Answer: Thick wire — because resistance decreases with
Answer: ( R = V/I = 12 / (2.5 \times 10^-3) = 4800 , \Omega )
Answer: ( \frac1R_p = \frac1100 + \frac150 + \frac1500 = \frac5 + 10 + 1500 = \frac16500 ) ( R_p = 31.25 , \Omega ) Current taken = ( V / R_p = 220 / 31.25 = 7.04 , \textA ) For iron: ( R = V/I = 220 / 7.04 \approx 31.25 , \Omega )
The solutions clarify a major misconception: Understanding this distinction is vital for solving the "Household Circuit" questions often asked in the final section.
Answer: Total resistance ( R = 5 + 8 + 12 = 25 , \Omega ) Current ( I = V/R = 6/25 = 0.24 , \textA ) (ammeter reading) Voltage across 12 Ω = ( I \times 12 = 0.24 \times 12 = 2.88 , \textV ) (voltmeter reading)
): The work done per unit positive charge to move it from infinity to a specific point. Unit: The SI unit is Volt ( ) .
By following this comprehensive guide to Class 10 Electricity NCERT Solutions, students can develop a thorough understanding of the concepts and principles of electricity, which will help them build a strong foundation in physics and prepare them for future studies.
Answer: Thick wire — because resistance decreases with increase in area.
The solutions demonstrate a step-by-step method:
A closed circuit is a circuit in which the current flows continuously, whereas an open circuit is a circuit in which the current does not flow.
Q7. The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below: I (amperes) : 0.5, 1.0, 2.0, 3.0, 4.0 V (volts) : 1.6, 3.4, 6.7, 10.2, 13.2 Plot V–I graph and calculate resistance. Slope ( \Delta V / \Delta I ) ≈ 3.3 Ω.
Answer: ( R = V/I = 12 / (2.5 \times 10^-3) = 4800 , \Omega )
Answer: ( \frac1R_p = \frac1100 + \frac150 + \frac1500 = \frac5 + 10 + 1500 = \frac16500 ) ( R_p = 31.25 , \Omega ) Current taken = ( V / R_p = 220 / 31.25 = 7.04 , \textA ) For iron: ( R = V/I = 220 / 7.04 \approx 31.25 , \Omega )
The solutions clarify a major misconception: Understanding this distinction is vital for solving the "Household Circuit" questions often asked in the final section.